![]() ![]() Next command we are gonna try for if you want to print the line number where the particular word is occurred. None of these solutions will work well if your filenames contain colons or newlines. How can I format my grep output to show line numbers. Now replace that match with itself and then a newline). Match zero of more non-colon characters followed by a colon. Here, the sed pattern splits at the second colon (the RE reads as Start at the beginning of the line. If you are just looking for a pattern within a specific directory, this should suffice: grep -hn FOO /your/path/.bar. This is also known as the grep show file name option. how to grep and show only file names that contain a string Ask Question Asked 8 years, 7 months ago. I assume, from your description, that you are doing this (I broke it into four lines to avoid horizontal scrolling) >tmp.txt When you use the grep command with the -r option to search for a pattern recursively in a directory, you can add the -H option to display the file name along with the matched lines. I've tried every technique I could find listed, involving find, grep and sed but I can't get the combo to do exactly what I want. You can use the -H option to always get the filename prepended to the output, or -h to never get it. The second example must have expanded to several file names, and grep does prepend the filename in that case. In that case, grep doesnt (by default) prepend the file name. to include everything after the 'Validating Classification' match). It doesn't even have to be limited to a one-line command or these specific commands. In your first example, the glob must have expanded to a single file. So grep -o will only show the parts of the line that match your regex (which is why you need to include the. You could even split it where you had: full/path/filename.ext:ln#:įor increased readability. When you use the grep command with the -r option to search for a pattern recursively in a directory, you can add the -H option to display the file name along. Or split the line so that I have: full/path/filename.ext:Įither way makes the results more readable. I want to do one of two things: Either cut off the path completely (last / before first :) and leave: filename.ext:ln#:contents of that line The problem is, this can result in very long lines, and too contracted to read easily because they include full/path/filename.ext:ln#:contents of that line. In my case, the command would be cover extensions pb, pbi, pbf, and pbp: find. That file won't match anything, but because there are two or more files in the command line, grep will show file names in its output. ![]() For PureBasic actually, but whatever the language, there are common elements involved. If your grep doesn't support the -H option (the greps on Solaris 10 do not), the typical workaround is to add the file /dev/null to grep's command line. I would also suggest that you postfix the regexp with $ in order to anchor it to the end (thus ensuring that the regexp matches filenames that ends with ".txt"): ls /some/path/some/dir/ | grep 'some_mask_.*\.I'm looking at source files. needs to be prefixed with a backslash since it has special significance as a regexp that matches a single character. DESCRIPTION grep searches the named input FILEs (or standard input if no files are named, or if a single hyphen-minus (-) is given as file name) for lines. Putting this together your command line version should be: ls /some/path/some/dir/ | grep 'some_mask_.*\.txt' | wc -lĪnd the script: iFiles=`ls /some/path/some/dir/ | grep 'some_mask_.*\.txt' | wc -l` In addition you need to write the pattern as a regexp and not as a wildcard match (which bash uses for matching). If you want to ensure that the pattern is used by grep then you need to enclose it in single quotes. The problem here is that grep some_mask_*.txt is expanded by the shell and not by grep, so most likely you have a file in the directory where grep is executed which matches some_mask_*.txtand that filename is then used by grep as a filter. ![]()
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